Question

Suppose the ratio of the number of primary coils to secondary coils in a transformer is 1500, i.e., Ns/Np = 1500. If the input voltage to the primary coil is 100 kV, what is the voltage in the secondary coil?

Answer 1

Given,

The ratio of the number of turns in secondary coils to that in primary coils is N_s/N_p=1500

the input voltage to the primary coil, V_p=100 kV

The transformer ratio is given by,

`(N_s)/(N_p)=(V_s)/(V_p)`

Where V_s is the voltage in the secondary coil.

On substituting the known values,

`\begin{gathered} 1500=(V_s)/(100*10^3) \\ \Rightarrow V_s=1500*100*10^3 \\ =150*10^6\text{ V} \\ =150\text{ MV} \end{gathered}`

Thus the voltage in the secondary coil is 150 MV