Question

Gaseous C2H4 reacts with O2 according to the following equation:

C2H4 (g) + 302 -> 2CO2 + H2O (g)
What volume of oxygen gas at STP is needed to react with 5.75 mol of C2H4?
A) 17.3 L
B) 42.9 L
C) 3.86 x 10^2 L
D) 1.29 x 10^2 L
E) Not enough information is given to solve the problem.

Answer 1

Each mole of gas occupies 22.4 L at STP.

Liters of gas = 17.25 x 22.4

= 3.86 x 10² L

Your correct answer is C 3.86 x 10^2 L

Step-by-step explanation:

Answer 2

Each mole of C₂H₄ requires 3 moles of O₂ to react.

5.75 moles of C₂H₄ will require:
3 x 5.75 = 17.25 moles

Each mole of gas occupies 22.4 L at STP.
Liters of gas = 17.25 x 22.4
= 3.86 x 10² L

The answer is C.