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How many moles of MgSiO3 are in 237g of the compound?
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How many moles of MgSiO3 are in 237g of the compound?

User Maxhungry
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For this, we first calculate molecular weight of MgSiO₃:
Atomic masses:
Mg = 24
Si = 28
O = 16

Mr = 24 + 28 + 16 x 3
Mr = 100

moles = mass / Mr
moles = 237 / 100
moles = 2.37
User DanielOfTaebl
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