Question

What are the solutions to the quadratic equation below? 3x^2+16x+21=0

Answer 1

C. x = -7/3 and x = -3

Explanation:

We have the following equation:

`3x^2+16x+21=0`

We solve for x:

`\begin{gathered} 16x=7x+9x \\ \\ \left(3x^2+7x\right)+\left(9x+21\right)=0 \\ \\ x\left(3x+7\right)+3\left(3x+7\right)=0 \\ \\ \left(3x+7\right)\left(x+3\right)=0 \\ \\ 3x+7=0\rightarrow3x=-7\rightarrow x=-(7)/(3) \\ \\ x+3=0\rightarrow x=-3 \end{gathered}`

Therefore, the correct answer is C. x = -7/3 and x = -3