Question

At the lowest point in the jump when the student is stationary, the extension of the bungee cord is 35 metres.

The bungee cord behaves like a spring with a spring constant of 40 N / m.
Calculate the energy stored in the stretched bungee cord.
Use the correct equation from the Physics Equations Sheet.

Please help me - need the answer and sum

Answer 1

when it is released,let say elongation at mean point is x. So at maximum elongation it'll become 2x. So 2x=35. x= 17.5m. Now energy stored in the stretched bungee cord is E= 1/2 kx^2.( k= 40N/m ). E= 1/2 x 40 x (17.5)^2 = 6125J. Hope it helps.