45.5k views
13 votes
What is the domain and range for
ƒ(x)= -√25-x^2

2 Answers

1 vote
remember with your answer: x=domain and y=range
User Jamie Mclaughlan
by
6.2k points
11 votes

First rearrange and solve for sqrt of 25(which is 5)

ƒ(x)= -x^2-5

range: y
\le5

domain: x x=can be anything because all values are defined

User Tmac
by
6.7k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.