Question

6. The standard equation of a circle with center (-4,1) and radius 6 isc.= 6.+a. (x + 4) + (-1) = 36b. (x+4)² + (x - 1)² = 6(x-4)+(y+1) = 6(x-4)² + (8 + 1)² = 36b.d.

Answer 1

Remember that

the equation of the standard form of the circle is equal to

`(x-h)^2+(y-k)^2=r^2`

where

(h,k) is the center

r is the radius

In this problem

looking at the graph

the center is (3,1)

radius is 2 units

substitute

`\begin{gathered} (x-3)^2+(y-1)^2=2^2 \\ (x-3)^2+(y-1)^2=4 \end{gathered}`

the answer is option b