Question

I am having ALOT of trouble with my ALGEBRA 2 MATH. Can somebody please help?!

Answer 1

Longer way:
1st year: $100
2nd year: $150
3rd year: $200
4th year: $250
5th: $300
6th: $350
7th: $400
8th: $450
9th: $500
10th: $550

Total = $100 + $150 + $200 + $250 + $300 + $350 + $400 + $450 + $500 + $550
= $3250

Shorter way:
Total =
`(n)/(2) (2a+(n-1)d)`,
where a is first term, n is number of terms, d is common difference (what is added/subtracted to get the next term in the sequence)
Total =
`(10)/(2) (2*100+(10-1)50) \\ = 5(200 + 9*50) \\ = 5(200+450) = 3250`