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Harry Wang · Answer 1 · 2017-05-21T21:35:11+0000

The difference will be

$6x^2+3x-8 - (x^2-3x+4) \\ = 6x^2-3x-8-x^2+3x-4 \\ = 5x^2 -12$ .
Remember that parentheses are needed for the second polynomial because the negative is distributed to all of its terms.

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