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A catapult hurls a cantaloupe from a heightof 12 feet at an initial velocity of 47 feetper second.n(t) = -16 t2 + 47t +12

User Somangshu Goswami
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1 Answer

19 votes
19 votes

To find the equation we use:


h(t)=-(1)/(2)gt^2+v_0t+h_0

Where h is the gravity, v0 is the intial velocity and h0 is the initial height.

Then, we replace the values,


\begin{gathered} g=32(ft)/(s^2);v_0=47(ft)/(s);h_0=12ft \\ h(t)=-(1)/(2)32t^2+47t+12 \\ h(t)=-16t^2+47t+12 \end{gathered}

User Hsnsd
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