Question

In the image, point A is the center of the circle. Which two line segments must be equal in length?

AH¯¯¯¯¯ and BC¯¯¯¯¯

HI¯¯¯¯ and BC¯¯¯¯¯

EF¯¯¯¯¯ and HI¯¯¯¯

EF¯¯¯¯¯ and AI¯¯¯¯

Answer 1

Answer:
`\overline{EF}=\overline{HI}`

Explanation:

Given: In the image, point A is the center of the circle.

Therefore every straight line segments passing from one to another point of circle through the center of circle A is the diameter of the circle.

Since,
`\overline{EF}` and
`\overline{HI}` are the line segments passing from side to side of circle through the center of circle A is the diameter of the circle, then both are representing diameter of the given circle.

Since, all the diameter of a circle has a unique length .

Hence, the line segments must be equal in length :

`\overline{EF}=\overline{HI}`

Answer 2

the answer

the true answer is
EF¯¯¯¯¯ and HI¯¯¯¯
proof

the line EF passes on A, and so does the line HI. both line are called diameter of the circle, that means
EF = HI