Question

-1 (r-3) ≥ 3(r + 5)


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Answer 1

Explanation:

Here you go

• Use PEMDAS

Step 1

-1 (r-3) ≥ 3(r + 5) Question

Step 2

-1 (r-3) ≥ 3(r + 5) Remove parenthesis

-r+3≥3r+15

Step 3

-r+3≥3r+15 Subtract 3r from sides

-4r+3≥15

Step 4

-4r+3≥15 Subtract 3

-4r≥12

Step 5

-4r≥12 Divide sides by 4

Answer

r≤-3

Answer 2

`\bold{Hey\ there!}`

`\bold{-1(r-3)\geq 3(r+5)}\\\bold{Distribute}\\\bold{-1r+3\geq 3r+15}\\\bold{SUBTRACT\ both\ of\ your\ sides\ by\ 3r}\\\bold{-1r+3-3r\geq 3r+15-3r}\\\bold{We\ get: -4r+3\geq 15}\\\bold{SUBTRACT\ both\ of\ your\ sides\ by\ 3}\\\bold{-4r+3-3\geq15-3}\\\bold{15-3=12}\\\bold{Equation: -4r \geq 12}\\\bold{DIVIDE\ both\ of\ your\ sides\ by\ -4}\\\bold{(-4r)/(-4)=(12)/(-4)}\\\bold{Cancel: (-4)/(-4)}\\\bold{Keep: (12)/(-4)}\\\bold{r\geq \underline{(12)/(-4)}}\\\bold{(12)/(-3)=r}`

`\boxed{\boxed{\bold{Answer: \boxed{\bold{r\leq -3}}}}}\huge\checkmark`

`\bold{Good\ luck\ on\ your\ assignment\ and\ enjoy\ your\ day!}\\\\\frak{Amphitrite1040:)}`