Question

The velocity of sound on a particular day outside is 331 meters/second. What is the frequency of a tone if it has a wavelength of 0.6 meters?

5.52 × 102 hertz
2.56 × 102 hertz
459 × 102 hertz
675 × 102 hertz
990 × 102 hertz

Answer 1

`5.52 \cdot 10^2` Hz

Step-by-step explanation:

For a wave, the relationship between velocity, wavelength and frequency is given by the wave equation:

`v=f\lambda`

where

v is the velocity

f is the frequency

`\lambda` is the wavelength

For the sound wave in this problem, we have:

v = 331 m/s

`\lambda=0.6 m`

Solving the equation for f, we find the frequency:

`f=(v)/(\lambda)=(331)/(0.6)=5.52\cdot 10^2 Hz`