Question

Write the expression in standard form.
five divided by quantity three minus fifteen i.

Answer 1

`(4)/(229)+(30i)/(229)`

Explanation:

Answer 2

The answer is
`(5)/(78)+ (25)/(78)i`


`(5)/(3-15i) =(5)/(3-15i)* (3+15i)/(3+15i) = (5(3+15i))/((3-15i)(3+15i)) \\ \\ a^(2) -b^(2) =(a+b)(a-b) \\ \\ 4 + (5(3+15i))/((3-15i)(3+15i)) = (15+75i)/( 3^(2)-(15i)^(2) ) = (15+75i)/(9-15^(2)i^(2)) \\ \\ i^(2)=-1 \\ \\ (15+75i)/(9-15^(2)i^(2)) =(15+75i)/(9-225*(-1)) =(15+75i)/(9+225) = (15+75i)/(234) = (3*5+3*25i)/(3*78) = (3(5+25i))/(3*78) = \\ \\ = (5+25i)/(78)= (5)/(78)+ (25i)/(78) =(5)/(78)+ (25)/(78)i`