168k views
1 vote
Students in Mr. Klein’s chemistry class are conducting an experiment to calculate the specific heat of a copper sample. Mr. Klein requires each lab team to repeat the experiment until their percent error is 2% or less. Percent error is calculated using observed values (those students calculate from their lab results) and the true value (the accepted value based on reference). The formula for percent error is: (observed – true) x 100 true If the accepted value for the specific heat of copper is 0.385 J/g°C, which of the following lab teams have an unresolved problem on their hands

a.

team 1: calculates 0.392 J/gºC
b.

team 2: calculates 0.395 J/gºC
c.

both teams
d.

neither team

User Him
by
7.7k points

2 Answers

4 votes

Final answer:

Team 2 has a percent error greater than 2% with their specific heat calculation of copper, while Team 1's percent error is within the acceptable range. Thus, Team 2 has an unresolved problem regarding their experiment.

Step-by-step explanation:

To determine which lab teams have an unresolved problem based on their calculation of the specific heat of copper, we first need to calculate the percent error using the given formula:

Percent error = ((observed - true) × 100) / true

Where 'observed' is the experimental value and 'true' is the accepted value.

The accepted value for the specific heat of copper is 0.385 J/g°C. We can now calculate the percent error for each team:

  • Team 1: ((0.392 - 0.385) × 100) / 0.385 = approximately 1.82%
  • Team 2: ((0.395 - 0.385) × 100) / 0.385 = approximately 2.60%

Team 1 has a percent error within the 2% limit set by Mr. Klein, while Team 2 has exceeded it. Therefore, the answer is:

b. team 2: calculates 0.395 J/gºC

User Water
by
8.8k points
5 votes
Percent error in team 1 value:
(0.392 - 0.385)/0.385 x 100
= 1.81%

Percent error in team 2 value:
(0.395 - 0.385)/0.385 x 100
= 2.60%

B. Team 2 has an unresolved issue in on their hands, resulting in greater than acceptable error.
User Piotr Rodak
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.