Question

Balanced complete ionic and net ionic equations

HClO4(aq)+Ca(OH)2(aq)→
this is what i got but its wrong H+(aq)+SO32−(aq)→SO2(g)+H2O(l)

H2SO4(aq)+Li2SO3(aq)→
H+(aq)+SO42−(aq)+2Li+(aq)+SO32−(aq)→2Li+(aq)+SO42−(aq)+SO2(g)+H2O(l)

Answer 1

(1) The net ionic equation will be,

`H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)`

(2) The net ionic equation will be,

`2H^+(aq)+SO_3^(2-)(aq)\rightarrow H_2O(l)+SO_2(g)`

Explanation :

In the net ionic equations, we are not include the spectator ions in the equations.

Spectator ions : The ions present on reactant and product side which do not participate in a reactions. The same ions present on both the sides.

(1) The balanced ionic equation will be,

`HClO_4(aq)+Ca(OH)_2(aq)\rightarrow Ca(ClO_4)_2(aq)+2H_2O(l)`

The ionic equation in separated aqueous solution will be,

`H^+(aq)+ClO_4^-(aq)+Ca^(2+)(aq)+2OH^-(aq)\rightarrow Ca^(2+)(aq)+2ClO_4^-(aq)+2H_2O(l)`

In this equation,
`Ca^(2+)\text{ and }ClO_4^-` are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

`H^+(aq)+2OH^-(aq)\rightarrow 2H_2O(l)`

(2) The balanced ionic equation will be,

`H_2SO_4(aq)+Li_2SO_3(aq)\rightarrow Li_2SO_4(aq)+H_2O(l)+SO_2(g)`

The ionic equation in separated aqueous solution will be,

`2H^+(aq)+SO_4^(2-)(aq)+2Li^+(aq)+SO_3^(2-)(aq)\rightarrow 2Li^+(aq)+SO_4^(2-)(aq)+H_2O(l)+SO_2(g)`

In this equation,
`Li^+\text{ and }SO_4^(2-)` are the spectator ions.

By removing the spectator ions from the balanced ionic equation, we get the net ionic equation.

The net ionic equation will be,

`2H^+(aq)+SO_3^(2-)(aq)\rightarrow H_2O(l)+SO_2(g)`

Answer 2

1) The balanced chemical equation will be :
2HClO4 (aq) + Ca(OH)2(aq) → Ca(ClO4)2 (aq) + 2H2O (l)

Ionic equation:
2H+(aq) + 2ClO4-(aq) +Ca2+(aq) + 2OH-(aq) → Ca2+(aq) + 2ClO4-(aq) +2H2O(l)

Net ionic equation:
2H+ (aq) + 2OH-(aq) → 2H2O(l)

2) Molecular equation:
H2SO4(aq) + Li2SO3(aq) → Li2SO4(aq) + SO2(g) + H2O(l)

Ionic equation:
2H+ (aq) + SO4 2-(aq) + 2Li+ (aq) + SO3 2-(aq) → 2Li+(aq) + SO4 2-(aq) + SO2(g) + H2O(l)

Net ionic equation:
2H+(aq) + SO3 2-(aq) → SO2(g) + H2O(l)