74.2k views
2 votes
In DEF DE=17 m angle =32 Find DF nearest tenth

In DEF DE=17 m angle =32 Find DF nearest tenth-example-1
User CountOren
by
7.8k points

2 Answers

6 votes
Since we are asked to find DF, and we are given an angle and the side opposite to it, we can use the sine function to find DF.
let x be the length of side DF.

sin(32)= 17/x
x= 17 / sin(32)
x= 32.08

approximately 32.1
User Jerryb
by
8.0k points
5 votes

Answer:

(A) 32.1

Explanation:

It is given that in ΔDEF, DE=17 and m∠F=32, thus

Using the trigonometry, we have


sinx=(Perpendicular)/(Hypotenuse)=(DE)/(DF)


sin32^(\circ)=(17)/(DF)


DF=(17)/(sin32^(\circ))


DF=(17)/(0.529)


DF=32.1

Therefore, the value of DF is 32.1.

Hence option A is correct.

User Istrel
by
8.3k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories