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What is the area of a rectangle with vertices (2, 3), (9, 3), (9, -2), and (2, -2)

User Ruchir
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I hope this helps you
What is the area of a rectangle with vertices (2, 3), (9, 3), (9, -2), and (2, -2)-example-1
User Jade
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Answer with explanation:

The Vertices of Rectangle are,A (2, 3), B(9, 3), C(9, -2), and D(2, -2).

Area of Rectangle = Length × Breadth


\text{Use Distance formula to find distance between two points}=\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2}}\\\\\text{Length}=√((9-2)^2+(3-3)^2)=√(7^2)=7\\\\\text{Breadth}=√((9-9)^2+(-2-3)^2)=√((-5)^2)=√(5^2)=5

So, Area of Rectangle = 7 × 5

= 35 square units

What is the area of a rectangle with vertices (2, 3), (9, 3), (9, -2), and (2, -2)-example-1
User Ashwin Patil
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8.2k points

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