Question

Abcd is a rectangle. Find the length of each diagonal. .AC= 3y/5 BD=3y-4

Answer 1

I hope this helps you

Answer 2

AC = BD = 1 unit

Explanation:

Given : length of diagonal of rectangle ABCD
`AC=(3y)/(5)` and
`BD=3y-4`

We have to find the length of diagonal.

We know In rectangle diagonal are of equal lengths.

Therefore, for rectangle ABCD diagonals AC= BD

Substitute the values, we get,

`(3y)/(5)=3y-4`

Cross multiply , we get

`3y=5(3y-4)`

On simplyfy , we get

`3y=15y-20`

Solve for y , we get

`15y-3y=20`

`12y=20`

Divide both side by 12, we get,

`y=(20)/(12)=(10)/(6)`

Thus, put the values of y in AC and BD to find the length of diagonals , we get,

`AC=(3y)/(5)=(3)/(5)*(10)/(6)=1`

Similarly for BC, we get,

`BD=3y-4=3((10)/(6))-4=5-4=1`

Thus, AC = BD = 1 unit