Question

Need the measure of the segment of jm on a rhombus. mk=24,jl=20 and m

Answer 1

Given,

The measure of the side MK is 24.

The measure of the side JL is 20.

The measure of angle MJL is 50 degree.

As known that,

The angle fromed by two diagonal of the rhombus is right angle.

The diagonal intersect each other at the midpoint,

`\begin{gathered} \text{Here,} \\ NM=(MK)/(2)=(24)/(2)=12 \\ JN=(JL)/(2)=(20)/(2)=10 \end{gathered}`

By Pythagorean theorem,

`\begin{gathered} JM^2=JN^2+MN^2 \\ JM^2=12^2+10^2 \\ JM^{}=\sqrt[]{144+10}0 \\ JM^{}=\sqrt[]{244} \\ JM=15.62 \end{gathered}`

The measure of the digonal is 15.62.