Question

Find the area and perimeter of fig ABCD where B=90 and angle DAC=90 degrees. AB=6cm and BC=8cm and DA=24cm

Answer 1

`96\ \text{cm}^2`

`17.1\ \text{cm}`

Explanation:

`DC` is the length of the hypotenuse of the triangle
`CED`.

So

`DC=√(ED^2+EC^2)\\\Rightarrow DC=√(16^2+6^2)\\\Rightarrow DC=17.1\ \text{cm}`

The perimeter of the
`ABCD` is
`17.1\ \text{cm}`

`AB+AD+DC+CB=6+24+17.1+8=55.1\ \text{cm}`

The Area of
`ABCD` would be

Area of rectangle ABEC+Area of triangle CED

`8* 6+(1)/(2)* 16* 6=96\ \text{cm}^2`

The area of the figure
`ABCD` is
`96\ \text{cm}^2`.