Question

A projectile is thrown upward so that its distance above the ground after t seconds is h(t)=-16t^2 + 570t. After how many seconds does it reach its maximum​ height?

Answer 1

It would only take 1 second to reach maximum height.

h(1)=−16(1^2)+(570)(1) after simplification, h would be 554.

If you kept increasing t, h would get smaller.