Question

Using the transformation T: (x, y) (x + 2, y + 1), find the distance named.

Find the distance CC'

Answer 1

I hope this helps you

Answer 2

The distance CC' is
`\sqrt5units`

Explanation:

Given the transformation T: (x, y) (x + 2, y + 1)

we have to find the distance CC'

Let coordinate of C are (a,b).

Now, by using transformation T the coordinates of C' are (a+2,a+1)

By using distance formula,

`CC'=√((x_2-x_1)^2+(y_2-y_1)^2)\\\\= √((a+2-a)^2+(b+1-b)^2)\\\\=√(4+1)=\sqrt5 units`

Hence, the distance CC' is
`\sqrt5units`