Question

Determine how many moles of Ba(OH)2 are required to completely neutralize 0.432 mole of HC2H3O2.

Answer 1

Answer: We need 0.216 moles of Ba(OH)2 to completely neutralize 0.432 moles of HC2H3O2.

Explanation:

• First we build the equation that represents the reaction between the Ba(OH)2 and the HC2H3O2.

2 CH3COOH + Ba(OH)2 = Ba(Ch3COO)2 + 2 H2O

• Second, we use the amount of moles giving (0.432 moles HC2H3O2) in order to calculate the moles of Ba(OH)2 produced, using the coefficients in the equation.

0.432moles CH3COOH x [1 mol Ba(OH)2/ 2 moles CH3COOH] = 0.216 moles Ba(OH)2

Answer 2

The balanced chemical reaction is:

HC2H3O2 (aq) +Ba(OH)2 (aq) --> H2O (l) +Ba(C2H3O2)2

We are given the amount of HC2H3O2 to be used in the reaction. We use this amount as the starting point of our calculations.

0.432 mol HC2H3O2 ( 1 mol Ba(OH)2 / 1 mol HC2H3O2 ) = 0.432 mol Ba(OH)2 needed

Hope this answers the question.