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Given f(x)=17-x^2, what is the average rate of change in f(x) over the interval [1, 5]?

User HoBa
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2 Answers

3 votes

Answer:A

Explanation:

(f(5) - f(1))/(5 - 1) =

(17 - 5^2 - (17 - 1^2))/4 =

(17 - 25 - 17 + 1)/4 = 6

User Fawad Shah
by
8.1k points
4 votes
For the answer to the question above, I'll show my to solution to the answer below.
average rate of change is
(f(5) - f(1))/(5 - 1) =

(17 - 5^2 - (17 - 1^2))/4 =

(17 - 25 - 17 + 1)/4 =
So the answer for this problem is
-6
I hope my answer helped you. Feel free to ask for more questions.
User Emrah Tuncel
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8.0k points