Question

If a 375 mL sample of water was cooled from 37.5 C to 0 C how much heat was lost in joules?

Answer 1

please, you have to apply the formula below:

Q=c∗m∗Δt

where Q is the energy lost,

c is the specific heat of water,

m is the mass of water involved,

so m=3.75 *10^-1 Kg

c=4,184 J/(Kg*°C)

delta t=37.5 °C

I hope my answer has come to your help. God bless and have a nice day ahead!