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38 votes
38 votes
the admissions fee at an amusement part is 1.75 for children and 6.60 for adults. on a certain day 262 people entered the park, and the admission fees collected totaled 1089$. How many children and how many adults were admitted?

User Ali Rasheed
by
2.6k points

1 Answer

9 votes
9 votes

Let c represent the number of children that were admitted

Let a represent the number of adults that were admitted

We were told that on a certain day 262 people entered the park. This means that

c + a = 262

Also, the admission fee for children is 1.75 and the admission fee for adults is 6.6. This means that the cost of c children's admission and a adult's admission is

1.75c + 6.6a

Given that the total amount that was collected for admission on that da was 1089, it means that

1.75c + 6.6a = 1089

From the first equation, c = 262 - a

We would substitute c = 262 - a into 1.75c + 6.6a = 1089. It becomes

1.75(262 - a) + 6.6a = 1089

458.5 - 1.75a + 6.6a = 1089

- 1.75a + 6.6a = 1089 - 458.5

4.85a = 630.5

a = 630.5/4.85

a = 130

c - 262 - a = 262 - 130

c = 132

132 children and 130 adults were admitted

User Trousout
by
3.1k points
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