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23 votes
(2k-7)/5+1-(k-1)/3
Pls help

User Tyrondis
by
4.4k points

2 Answers

4 votes

Answer:


(k-1)/(15)

Explanation:


((2k - 7))/(5) + 1 - ((k-1))/(3)


(3(2k -7))/(3 ( 5)) + (15 * 1)/(15 * 1) - (5(k-1))/(5 * 3)


(6k - 21)/(15) + (15)/(15) - (5k - 5)/(15)


((6k - 21) + 15 - (5k - 5))/(15)


((6k - 6) - (5k - 5))/(15)


(6k - 6 - 5k + 5)/(15)


(k - 1)/(15) <------This is your answer

Hope this helps!

User JordanBelf
by
5.2k points
11 votes

Answer:

2k/5 + 1 + -k+1/3

Explanation:

(2k - 7)/5 + 1 - 1 x (k - 1)/3

Simplify

Combine multiplied terms into a single fraction

2k - 7/5 + 1 - 1 x k - 1/3

2k- 7/5 + 1 + -1(k - 1)/3

Distribute

2k - 7/5 + 1 + -1(k - 1)/ 3

2k - 7/5 + 1 + = -k + 1/3

Solution

2k - 7/5 + 1 + -k + 1/3

User Vulcan
by
4.9k points