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What is the absolute value of 4+7i is equal to the square root of ______

User Prewett
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2 Answers

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the answer too your question is 65 it is equal to the square root of 65
User Rodolfo Faquin
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4 votes

Answer:

The absolute value of 4+7i is equal to
\sqrt{4^(2)+7^(2)}.

The absolute value of the 4+7i be
√(65).

Explanation:

The absolute value is given by .

|a + bi| =
\sqrt{a^(2)+b^(2)}

Now find the absolute value of the 4+7i.

|4+ 7i|=
\sqrt{4^(2)+7^(2)}

|4+ 7i| =
√(16+49)

|4+ 7i| =
√(65)

Therefore the absolute value of the 4+7i is
√(65) .

User Nicolas Buduroi
by
8.2k points

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