Question

8. You have 600 grams of Ru3P7. How many moles are present?

Answer 1

1.15 mol

Step-by-step explanation

Given:

Mass of Ru₃P₇ = 600 grams

What to find:

The number of moles of Ru₃P₇ present in 600 grams of Ru₃P₇.

Step-by-step solution:

Step 1: Find the molar mass of Ru₃P₇.

From the Periodic Table, the atomic masses of (Ru = 101.07, P = 30.97).

Molar mass of Ru₃P₇ = (3 x 101.07) + (7 x 30.97)

Molar mass of Ru₃P₇ = 303.21 + 216.79

Molar mass of Ru₃P₇ = 520 g/mol

Step 2: Find the moles of Ru₃P₇.

Using the mole formula below, the number of moles can be calculated:

`\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles=\frac{600\text{ }g}{520\text{ }g\text{/}mol}=1.15\text{ }mol \end{gathered}`

Therefore, the number of moles of Ru₃P₇ present in 600 grams of Ru₃P₇ = 1.15 mol.