Question

NEEDED ASAP PLEASE

A relation is plotted as a linear function on the coordinate plane starting at point C (0,−1)(0,−1) and ending at point D (2,−11)(2,−11) . What is the rate of change for the linear function and what is its initial value? Select from the drop-down menus to correctly complete the statements.The rate of change is -11, -5, 0, 5.and the initial value is -11, -2, -1, 0.

Answer 1

-5,-1

Explanation:

I took the test!

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Answer 2

The rate of change for your linear function is the slope. You can use the points C and D to calculate it.
slope = (y2 - y1)/(x2 - x1) = (-11 - (-1))/(2 - 0) = -10/2 = -5
I'm not sure what is meant by initial value, but maybe you are looking for the y-intercept of the line.

The y-intercept is the point where the line crosses the y axis, so where x = 0. You have that because your line passes through the point (0, -1). When x = 0, y = -1.