99.9k views
0 votes
Using the quadratic formula b²-4b+4=0

2 Answers

0 votes

b^2-4b+4=0\\ (b-2)^2=0\\ b-2=0\\ b=2
User Chris Rosete
by
8.1k points
2 votes
If you need to use the Quadratic Formula, it could also look something like this:
(1)b² + (-4)b + (4) = 0
These represent a, b, and c in their respective order.
The equation itself is:
(-b (+/-) √(b² - 4ac))/2a
So, plug 'em in:
(4 (+/-) √(-4² - 4·1·4))/2·1
And then solve:
(4 (+/-) √(16 - 16))/2
(4 (+/-) 0)/2
4/2
2
User Trevor Alyn
by
8.2k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories