Question

Henry throws a ball with a velocity of 30 m/s, how much time will it take the ball to reach a height of 45 m?

Answer 1

t = 1.24 seconds

Step-by-step explanation:

Given that,

Velocity of the ball, u = 30 m/s

Height, h = 45 m

We need to find how much time will it take the ball to reach a height of 45 m. Let the time be t.

Using the second equation of motion to find it.

`h=ut+(1)/(2)at^2\\\\45=30t+(1)/(2)* 9.8* t^2\\\\45=30t+4.9t^2\\\\30t+4.9t^2-45=0\\\\t=1.24\ s\ \text{and}\ -7.36\ s`

Neglecting negative value,

The ball will reach to a height of 45 m in 1.24 seconds.