Question

What is the result of isolating y2 in the equation below?

(x - 2)^2 + y2 = 64

A. y2 = -x2 + 4x + 60
B. y2 = -x2 + 4x + 4
C. y2 = 64 - x2
D. y2 = x2 + 4x + 60

Answer 1

I hope this helps you

Answer 2

Answer with explanation:

The given equation which represents a circle having center at, (2,0) and radius =8 is,

`(x - 2)^2 + y^2 = 64\\\\y^2=64 - (x-2)^2\\\\y^2=64 - (x^2-4 x +4)\\\\ y^2=64 -x^2+4 x-4\\\\y^2=60+4 x-x^2`

Result of isolating y² in the equation below, gives

Option A

`y^2=60+4 x-x^2`