Question

4. You have 300 grams of Ag3N. How many moles are present?

Answer 1

0.8886 mol

Step-by-step explanation

Given:

Mass of Ag₃N = 300 grams

What to find:

The number of moles present in 300 grams of Ag₃N.

Step-by=step solution:

From the Periodic Table; the 1 mole of Ag₃N has 337.61 g/mol

Therefore, the number of moles present in 300 grams Ag₃N can be calculated using the mole formula below:

`\begin{gathered} Moles=\frac{Mass}{Molar\text{ }mass} \\ \\ Moles=\frac{300\text{ }g}{337.61\text{ }g\text{/}mol}=0.8886\text{ }mol \end{gathered}`

The number of moles present in 300 grams of Ag₃N is 0.8886 mol.