Question

find the equation of the circle with the given center and radius:a. Center (0,0) and r = √13b. Center (-8, -1) and r = 9

Answer 1

`x^2+y^2=13`

Explanation:

We have that the equation of the circle is given by the following equation

`\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where (h, k) is the center and r is the radius} \end{gathered}`

Replacing:

`\begin{gathered} (x-0)^2+(y-0)^2=\sqrt[]{13}^2^{} \\ x^2+y^2=13 \end{gathered}`