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What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
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Jun 9, 2017
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What volume would 3.01•1023 molecules of oxygen gas occupy at STP?
Chemistry
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Gboffi
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the answer is c) 11.2 L
edge 2021
Ye Lin Aung
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Jun 9, 2017
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First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2
Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2
Ricco D
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Jun 13, 2017
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