Question

What volume would 3.01•1023 molecules of oxygen gas occupy at STP?

Answer 1

the answer is c) 11.2 L

edge 2021

Answer 2

First, find moles of oxygen gas: (3.01 x10^23 molec.)/(6.02 x10^23) =0.5mol O2


Second, multiply moles by the standard molar volume of a gas at STP:(0.5mol)(22.4L) = 11.2L O2