234k views
3 votes
What are the sine, cosine, and tangent of Θ = 3 pi over 4 radians?

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = 1

sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = 1

sin Θ = negative square root 2 over 2; cos Θ = square root 2 over 2; tan Θ = -1

User Dantix
by
7.9k points

1 Answer

2 votes
the unique answer is A
sin Θ = square root 2 over 2; cos Θ = negative square root 2 over 2; tan Θ = -1

(just put the Θ in the trigonometry circle)
User Joffre
by
7.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.