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The equation h = -16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum
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Apr 21, 2017
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The equation h = -16t^2 + 32t + 9 gives the height of a ball, h, in feet above the ground, at t seconds after the ball is thrown upward. How many seconds after the ball is thrown will it reach its maximum height? What is its maximum height?
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Buddhi Chamalka
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It would take 1 second to reach its maximum height, which would be 25 feet.
h=
−
16
(
1^2)
+
(32)
(1)
+
9 If you substituted t as 1, you would find that after simplification, h would be 25.
You would find out that as you increased t, h would get smaller.
Ramkrishna Sharma
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Apr 26, 2017
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Ramkrishna Sharma
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