Question

What is the general form of the equation for the given circle?

x2 + y2 − 8x − 8y + 23 = 0

x2 + y2 − 8x − 8y + 32 = 0

x2 + y2 − 4x − 4y + 23 = 0

x2 + y2 + 4x + 4y + 9 = 0

Answer 1

A ) x² + y² - 8 x - 8 y + 23 = 0

Explanation:

hope i helped

Answer 2

Coordinates of the center: ( 4, 4 )
The radius: r = 7 - 4 = 3
The equation of a circle:
( x - 4 )² + ( y - 4 )² = 3²
x² - 8 x + 16 + y² - 8 y + 16 = 9
x² + y² - 8 x - 8 y + 32 - 9 = 0
Answer:
A ) x² + y² - 8 x - 8 y + 23 = 0