Question

Find the ratios for cos A and sin B.A543Not drawn to scalecos A =sin B:B

Answer 1

cos A = 4/5

sin B = 4/5

Explanation

Cosine formula

`\cos(angle)=\frac{adjacent\text{ side}}{hypotenuse}`

Considering angle A, the adjacent side is AC and the hypotenuse of the triangle is AB, then:

`\begin{gathered} \cos(A)=(AC)/(AB) \\ \cos(A)=(4)/(5) \end{gathered}`

Sine formula

`\sin(angle)=\frac{opposite\text{ side}}{hypotenuse}`

Considering angle B, the opposite side is AC and the hypotenuse of the triangle is AB, then:

`\begin{gathered} sin(B)=(AC)/(AB) \\ s\imaginaryI n(B)=(4)/(5) \end{gathered}`