Question

A circuit with a 11 V battery a 13 Ω resistor and 13 Ω resistor in series. What is the current throughout the circuit?

Answer 1

`0.42A`

Step-by-step explanation

To find the current throughout the circuit, we have to apply the relationship between voltage and current using Ohm's law:

`V=IR`

where V = voltage; I = current; R = resistance

Since the resistors are in series, the total resistance of the circuit is the sum of the individual resistances of the resistors.

Hence, the resistance is:

`\begin{gathered} R=R_1+R_2_{} \\ R=13+13 \\ R=26\Omega \end{gathered}`

Therefore, the current throughout the circuit is:

`\begin{gathered} 11=I\cdot26 \\ I=(11)/(26) \\ I\approxeq0.42A \end{gathered}`

That is the answer.