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Limit as n approaches infinity of 1/n[(1/n)^9+(2/n)^9+(3/n)^9+...+(n/n)^9

User KingJinho
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As each term is convergent thus sum is also convergent.... Therefore as n tends to infinity ,the each term converges to 0 .thus sum is also converges to 0+0+0+0+.........n times=0
User Tdihp
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