148k views
5 votes
Limit as n approaches infinity of 1/n[(1/n)^9+(2/n)^9+(3/n)^9+...+(n/n)^9

User KingJinho
by
7.9k points

1 Answer

6 votes
As each term is convergent thus sum is also convergent.... Therefore as n tends to infinity ,the each term converges to 0 .thus sum is also converges to 0+0+0+0+.........n times=0
User Tdihp
by
8.9k points