Question

Fill in the missing numbers to complete the factorization. Some of the numbers could be negative. Type the numbers in increasing order.

x 3 + 2x 2 - x - 2 = (x +

Answer 1

`x^3+2x^2-x-2=(x+1)(x-1)(x+2)`

Explanation:

We have given equation :
`x^3+2x^2-x-2=(x+`

To find : the missing numbers

We have given that missing numbers complete the factorization

so, we find the factors of the given equation

`x^3+2x^2-x-2=0`

with the help of graph(attached) we find the roots of the equation or you can also take help of hit n trial method.

Roots of the equation are = 1,-1,-2

therefore the factors are (x+1)(x-1)(x+2)

and the missing terms are the factors of the equation = (x+1)(x-1)(x+2)

Answer 2

`(x-1)>(x+1)>(x+2)`

Explanation:

The given equation is:

`x^3+2x^2-x-2`

Factorizing the above equation, we get

`(x+1)(x^2+x-2)`

`(x+1)(x^2+2x-x-2)`

`(x+1)(x(x+2)-1(x+2))`

`(x+1)(x-1)(x+2)`

which is the required factorized form of the given equation.

Now, the numbers in increasing order are:

`(x-1)>(x+1)>(x+2)`