Question

A waste collection tank can hold 18,754 kg of methanol, which has a density of 0.788 g/cm3. What is the volume of the waste collection tank?

Answer 1

Answer : The volume of the waste collection tank is 23799.5 L

Explanation :

Density : It is defined as the mass contained per unit volume.

Formula used for density :

`Density=(Mass)/(Volume)`

Given :

Mass of methanol = 18754 kg = 18754000 g (1 kg = 1000 g)

Density of methanol =
`0.788g/cm^3`

Now put all the given values in the above formula, we get:

`0.788g/cm^3=(18754000g)/(Volume)`

`Volume=23799492.38cm^3=23799492.38mL=23799.5L`

Conversion used :
`(1cm^3=1mL=0.001L)`

Therefore, the volume of the waste collection tank is 23799.5 L

Answer 2

Step-by-step explanation:

Density is defined as the mass of the substance divided by the volume of the substance.

Mathematically, Density =
`(mass)/(volume)`

Since, it is given that mass is 18,754 kg and density is 0.788 g/
`cm^(3)`. We know that there are 1000 grams in 1 kg.

So, 18,754 kg equals 18,754000 grams.

Hence, calculate the volume of the waste collection tank as follows.

Density =
`(mass)/(volume)`

0.788 g/
`cm^(3)` =
`(18754000 g)/(volume)`

volume = 23799492.38
`cm^(3)`

It is known that 1
`cm^(3)` equals 0.001 liter. So, 23799492.38
`cm^(3)` equals 23799.49 liters.

Thus, we can conclude that volume of the waste collection tank is 23799.49 liters.