Question

Solve the system of equations using substitution.
y= 3/4x-7
4x- 6y=50

Answer 1

Y=3/4x-7
4x-6y=50

4x-6y=50
4x-6(3/4x-7)=50
4x-18/4x+42=50
-1/2x=8
x=-16

y=3/4(-16)-7
y=-12-7
y=-19

Answer 2

`\begin{cases} y= (3 )/(4)x-7 \\ 4x- 6y=50 \end{cases}\\ \\\begin{cases} y= (3 )/(4)x-7 \\ 4x- 6((3 )/(4)x-7)=50 \end{cases}\\ \\\begin{cases} y= (3 )/(4)x-7 \\ 4x- (9 )/(2)x+42=50 \end{cases}\\ \\ \begin{cases} y= (3 )/(4)x-7 \\ 4x- 4(1 )/(2)x =50 -42\end{cases}`


`\begin{cases} y= (3 )/(4)x-7 \\ - (1 )/(2)x =8 \ \ /*(-2)\end{cases}\\ \\ \begin{cases} y= (3 )/(4)*(-16)-7 \\ x =-16\end{cases}\\ \\ \begin{cases} y= -12-7 \\ x =-16\end{cases} \\ \\\begin{cases} y= -19 \\ x =-16\end{cases}`