Question

Find the possible value or values of z in the quadratic equation z2 – 4z + 4 = 0. A. z = 2√ 2 + 2, z = −√ 2 + 2 B. z = 2 C. z =√ 2 + 2, z = −√ 2 + 2 D. z = 10, z = 6

Answer 1

z=2

Explanation:

im not going to explain it because the other person explained it but i will just show you a trick, might not always work but for the equation z^2 -4z+4=0 if you try putting 2 in for z it will be true 0=0... (2)^2 -4(2) +4= 0

Answer 2

Start with the given equation
Let's use the quadratic formula to solve for z
Start with the quadratic formula
Break up the expression.
Combine like terms
Simplify
So the solution is z=2 (with a multiplicity of 2) z^2 - 4z + 4 = 0
Factor to get:
(z-2)(z-2) = 0
Since the product is zero, one of the factors must be zero:
z-2 = 0
Therefore z = 2