pOH = - log[OH^-]
pOH = - log[10^-6]
pOH = - (-6)
pOH = 6
knowing the ionization equation between pH and pOH in a solution at T = 25 degrees Celsius.
pH + pOH = 14
pH = 14 - pOH
pH = 14 - (6)
pH = 8.
I believe the pH of a substance with 10^-6 M of OH, would be 8.