Question

The Probability that one bulb is red and one is yellow?

27 Bulbs contains 11 red, 9 yellow and 7 purple

Answer 1

`(11)/(39)`

Explanation:

Given,

The number red bulb = 11,

Yellow bulb = 9,

Purple = 7,

Total bulbs = 11 + 9 + 7 = 27,

If two bulbs are taken,

Then, the probability that one bulb is red and one is yellow

`=\frac{^(11)C_1* ^9C_1}{{27}^C_2}`

`=(11* 9)/((27!)/(2!* 25!))`

`=(99)/((27* 26)/(2))`

`=(99)/(27* 13)`

`=(11)/(39)`

Answer 2

I have a solution here where:

A bag of 27 Tulip bulbs contain 10 red tulip bulbs, 8 Yellow, and 9 purple tulip bulbs.

Red-
10/27= .37
times 100 gives percentage
=37%

Yellow-
8/27= .3
times 100 gives percentage
30%

You can use my solution in answering the question on your own!

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!