Question

The height (in meters) of a projectile shot vertically upward from a point 2 m above ground level with an initial velocity of 24.5 m/s is

h = 2 + 24.5t − 4.9t2
after t seconds. (Round your answers to two decimal places.)

Answer 1

The question requires solving various problems involving projectile motion, a physics topic, using kinematic equations and algebraic techniques to determine height, flight time, and impact speeds.

Step-by-step explanation:

The question involves calculating various aspects of projectile motion, which is a topic in physics. In these problems, equations of motion are used to determine the maximum height, time of flight, and speed at impact of objects thrown or released from certain heights.

Example Calculations

• To calculate the maximum height, you can use the equation h = 2 + 24.5t − 4.9t2 and look for the time t when the velocity is zero.
• The time it takes for an object to reach the ground can be calculated by setting the height equation to zero and solving for t.
• To find the speed at impact, you use the conservation of energy or the kinematic equations to relate the initial velocity, acceleration due to gravity, and the distance fallen.

Each of these problems requires an understanding of the kinematic equations for vertical projectile motion and the ability to apply algebraic and calculus techniques.

Answer 2

The height (in meters) of a projectile shot vertically upward from a point 3 m above ground level with an initial velocity of 24.5 m/s is h = 3 + 24.5t − 4.9t2 after t seconds.

With what velocity does it hit the ground?
Vf = √Voy^2+2gh = √24.5^2+6*9.8 = 25.67 m/sec
I hope my answer helped you, though you didn't indicate what your question was. I assumed that you are looking for the velocity when it hits the ground.